How does printf() work without variable list in its argument? -

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the following code:

#include<stdio.h> void main() {      int i=100,j=200;     printf("%d.....%d");    }

gives 200.....100 output. explain how printf works without datalist

it provides warning @ compile time (warning: few arguments format), and not documented, therefore it's undefined behaviour , should not used. different compilers have different behaviours , behaviour may change between versions of same compiler.

try reading on wikipedia more info.


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