regex - R regular expression replace :75% -> 0.75 -

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surely naive question i'm in r , have expression

v <- "gastrula:75%"

that want replace "gastrula0.75"

i tried things :

v <- sub("\\.(\\d+)%","0.\\1",v) v <- sub("[:punct:](\\d)\\1+[:punct:]","0.\\1",v)

but didn't find worked.

here's possibility:

v <- "gastrula:75%" str <- unlist(strsplit(v,":")) paste0(str[1], as.numeric(gsub("%","",str[2]))/100)

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