xml - Xslt copy element into renamed element -

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i'm struggling xslt produce i'm after.

i have following xml 

<data>     <things>         <name>a</name>     </things>     <other>         <type>b</type>     </other> </data>

and want output xml be

<data>     <stuff>         <name>a</name>         <type>b</type>     </stuff>     </data>

i have following xslt far doesn't produce i'm after

<xsl:stylesheet version="1.0"   xmlns:xsl="http://www.w3.org/1999/xsl/transform"  >  <xsl:output omit-xml-declaration="yes" indent="yes"/>  <xsl:strip-space elements="*"/>   <xsl:template match="node()|@*" name="identity">      <xsl:copy>        <xsl:apply-templates select="node()|@*"/>      </xsl:copy>  </xsl:template>    <xsl:template match="data/things">     <xsl:element name="stuff">       <xsl:apply-templates select="@*|node()"/>     </xsl:element>   </xsl:template>    <xsl:template match="data/other">     <xsl:element name="stuff">       <xsl:apply-templates select="@*|node()"/>     </xsl:element>   </xsl:template>  </xsl:stylesheet>

this simple appreciated

this simple

well, be:

<xsl:stylesheet version="1.0"  xmlns:xsl="http://www.w3.org/1999/xsl/transform"> <xsl:output method="xml" omit-xml-declaration="yes" version="1.0" encoding="utf-8" indent="yes"/> <xsl:strip-space elements="*"/>  <!-- identity transform --> <xsl:template match="@*|node()">     <xsl:copy>         <xsl:apply-templates select="@*|node()"/>     </xsl:copy> </xsl:template>  <xsl:template match="/data">     <xsl:copy>         <stuff>             <xsl:apply-templates select="*/*"/>         </stuff>     </xsl:copy> </xsl:template>  </xsl:stylesheet>

or, if want explicit, make second template:

<xsl:template match="/data">     <xsl:copy>         <stuff>             <xsl:apply-templates select="things/name | other/type"/>         </stuff>     </xsl:copy> </xsl:template>

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