regex - How to generate Regexp matcher for String with even Number? -

this question has answer here:

• regular expression match odd or number 3 answers

there're regexp digit everywhere: example:

4 

but regexp number: example :

568 

regex designed find pattern in string, not find , recognize e.g. (extract prime number string). should better extract consecutive digits , check (num % 2 == 0).

but still if want stick regex, pattern provided in comments above needs little bit adjustment case.

you may try pattern:

\b(\d+??[02468])\b 

demo

edit:

i didn't interacted grep before, from doc found grep doesn't support features supported regex engine other languages.

so adjusted pattern based on allowed input, try pattern:

^([0-9]+[24680]|[02468])$ 

tested here on following inputs:

(z + (758+1) + x) (z + (757+1) + x) (z + (123+1) + x) 757 758 123 144 13 14 2 

and result is:

758 144 14 2 

hope helps now!